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Simplifying 5c3 = 20c Solving 5c3 = 20c Solving for variable 'c'. Reorder the terms: -20c + 5c3 = 20c + -20c Combine like terms: 20c + -20c = 0 -20c + 5c3 = 0 Factor out the Greatest Common Factor (GCF), '5c'. 5c(-4 + c2) = 0 Factor a difference between two squares. 5c((2 + c)(-2 + c)) = 0 Ignore the factor 5.Subproblem 1
Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0Subproblem 2
Set the factor '(2 + c)' equal to zero and attempt to solve: Simplifying 2 + c = 0 Solving 2 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + c = 0 + -2 c = 0 + -2 Combine like terms: 0 + -2 = -2 c = -2 Simplifying c = -2Subproblem 3
Set the factor '(-2 + c)' equal to zero and attempt to solve: Simplifying -2 + c = 0 Solving -2 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + c = 0 + 2 c = 0 + 2 Combine like terms: 0 + 2 = 2 c = 2 Simplifying c = 2Solution
c = {0, -2, 2}
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